y^2-11y+2.4=0

Solution for y^2-11y+2.4=0 equation:

y^2-11y+2.4=0

a = 1; b = -11; c = +2.4;
Δ = b2-4ac
Δ = -112-4·1·2.4
Δ = 111.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{111.4}}{2*1}=\frac{11-\sqrt{111.4}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{111.4}}{2*1}=\frac{11+\sqrt{111.4}}{2}
$